x^2-56x-160=0

Solution for x^2-56x-160=0 equation:

x^2-56x-160=0

a = 1; b = -56; c = -160;
Δ = b2-4ac
Δ = -562-4·1·(-160)
Δ = 3776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3776}=\sqrt{64*59}=\sqrt{64}*\sqrt{59}=8\sqrt{59}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-8\sqrt{59}}{2*1}=\frac{56-8\sqrt{59}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+8\sqrt{59}}{2*1}=\frac{56+8\sqrt{59}}{2}
$